A solid is made of two elements X and Z. The | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $CCP$ (cubic close packing) arrangement,the number of octahedral voids is equal to the number of atoms,while the number of tetrahedral voids

Vedclass · Accepted Answer

$X_2Z$

Vedclass · Answer

(C) In a $CCP$ (cubic close packing) arrangement,the number of octahedral voids is equal to the number of atoms,while the number of tetrahedral voids is double the number of atoms.Let the number of atoms of $Z$ in the $CCP$ arrangement be $n$.Then,the number of tetrahedral voids is $2n$.Since atoms $X$ occupy all the tetrahedral sites,the number of atoms of $X$ is $2n$.The ratio of atoms $X:Z$ is $2n:n$,which simplifies to $2:1$.Therefore,the formula of the compound is $X_2Z$.

$A$ solid is made of two elements $X$ and $Z$. The atoms $Z$ are in $CCP$ arrangement while the atoms $X$ occupy all the tetrahedral sites. What is the formula of the compound?

Similar Questions

$A$ body-centred cubic $(BCC)$ lattice is made up of two different types of atoms $X$ and $Y$. Atom $X$ occupies the body centre and atoms $Y$ occupy the corner positions. One of the corners is left unoccupied per unit cell. The empirical formula of it is

Calculate the total number of tetrahedral and octahedral voids in $0.4 \ mol$ of a compound having such voids in it.

How many tetrahedral voids are occupied in diamond? (in percentage)

Explain three-dimensional close packing from two-dimensional square close-packing. How is the primitive cubic unit cell obtained?

Calculate the packing efficiency in a simple cubic metal crystal.

Vedclass Test Series

Exam Paper Generator

Online Exam Module