A solution containing Na_2CO_3 and NaOH requi | vedclass

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(B) Let the mass of $Na_2CO_3$ be $x \ g$ and $NaOH$ be $y \ g$.Using phenolphthalein indicator,$NaOH$ is completely neutralized and $Na_2CO_3$ is con

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(B) Let the mass of $Na_2CO_3$ be $x \ g$ and $NaOH$ be $y \ g$.Using phenolphthalein indicator,$NaOH$ is completely neutralized and $Na_2CO_3$ is converted to $NaHCO_3$ (half-neutralization).$Meq. \ of \ NaOH + Meq. \ of \ Na_2CO_3 (half) = 300 	imes 0.1 = 30$.$\frac{y}{40} 	imes 1000 + \frac{x}{106} 	imes 1000 = 30$ ... $(1)$When methyl orange is added,the remaining $NaHCO_3$ is neutralized.$Meq. \ of \ Na_2CO_3 (remaining \ half) = 25 	imes 0.2 = 5$.$\frac{x}{106} 	imes 1000 = 5$ ... $(2)$From $(2)$,$\frac{x}{106} 	imes 1000 = 5$.Substitute this into $(1)$:$\frac{y}{40} 	imes 1000 + 5 = 30$$\frac{y}{40} 	imes 1000 = 25$$y = \frac{25 	imes 40}{1000} = 1 \ g$.

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