A solution contains 1 mole of water and 4 m | vedclass

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Question

(A) Given: $n_{	ext{water}} = 1 \ mole$,$n_{	ext{ethanol}} = 4 \ mole$. Total moles $= 1 + 4 = 5 \ moles$. Mole fraction of water $(X_{	ext{water}}

Vedclass · Accepted Answer

$0.2$ water + $0.8$ ethanol

Vedclass · Answer

(A) Given: $n_{	ext{water}} = 1 \ mole$,$n_{	ext{ethanol}} = 4 \ mole$. Total moles $= 1 + 4 = 5 \ moles$. Mole fraction of water $(X_{	ext{water}}) = \frac{n_{	ext{water}}}{n_{	ext{total}}} = \frac{1}{5} = 0.2$. Mole fraction of ethanol $(X_{	ext{ethanol}}) = \frac{n_{	ext{ethanol}}}{n_{	ext{total}}} = \frac{4}{5} = 0.8$. Thus,the mole fraction of water is $0.2$ and ethanol is $0.8$.

$A$ solution contains $1 \ mole$ of water and $4 \ mole$ of ethanol. The mole fraction of water and ethanol will be

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