(B) Mass of solute (ethyl alcohol) $= 1 \ mole \times 46 \ g \ mol^{-1} = 46 \ g$.Mass of solvent (water) $= 9 \ mole \times 18 \ g \ mol^{-1} = 162 \

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(B) Mass of solute (ethyl alcohol) $= 1 \ mole \times 46 \ g \ mol^{-1} = 46 \ g$.Mass of solvent (water) $= 9 \ mole \times 18 \ g \ mol^{-1} = 162 \ g$.Total mass of solution $= 46 \ g + 162 \ g = 208 \ g$.Mass percent of solute $= \frac{\text{Mass of solute}}{\text{Total mass of solution}} \times 100$.Mass percent $= \frac{46}{208} \times 100 = \frac{4600}{208} \approx 22.11 \%$.The integer value is $22$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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$A$ solution is prepared by adding $1 \ mole$ of ethyl alcohol in $9 \ mole$ of water. The mass percent of solute in the solution is. . . . . . . (Integer Answer)
(Given : Molar mass in $g \ mol^{-1}$ Ethyl alcohol : $46$,
water : $18$)

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A
$20$
B
$22$
C
$30$
D
$35$

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$A$ solution is prepared by adding $1 \ mole$ of ethyl alcohol in $9 \ mole$ of water. The mass percent of solute in the solution is. . . . . . . (Integer Answer)(Given : Molar mass in $g \ mol^{-1}$ Ethyl alcohol : $46$,water : $18$)

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Find out the molarity of a solution when $0.01 \ mol$ of a substance is dissolved in $10 \ g$ of water. (in $M$)

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$A$ solution is prepared by adding $1 \ mole$ of ethyl alcohol in $9 \ mole$ of water. The mass percent of solute in the solution is. . . . . . . (Integer Answer)
(Given : Molar mass in $g \ mol^{-1}$ Ethyl alcohol : $46$,
water : $18$)