A solution of copper sulphate (CuSO_4) is ele | vedclass

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(B) According to Faraday's law of electrolysis,the mass $W$ deposited is given by $W = Z 	imes i 	imes t$. Here,$Z$ is the electrochemical equivalen

Vedclass · Accepted Answer

$0.2938$

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(B) According to Faraday's law of electrolysis,the mass $W$ deposited is given by $W = Z 	imes i 	imes t$. Here,$Z$ is the electrochemical equivalent,$i$ is the current in amperes,and $t$ is the time in seconds. For $Cu^{2+} + 2e^- ightarrow Cu$,the equivalent weight of copper is $\frac{63}{2} = 31.5 \, g \, 	ext{eq}^{-1}$. $Z = \frac{	ext{Equivalent weight}}{96500} = \frac{31.5}{96500}$. Given $i = 1.5 \, A$ and $t = 10 \, 	ext{minutes} = 600 \, 	ext{seconds}$. $W = \frac{31.5}{96500} 	imes 1.5 	imes 600 = 0.2938 \, g$.

$A$ solution of copper sulphate $(CuSO_4)$ is electrolysed for $10 \, \text{minutes}$ with a current of $1.5 \, \text{amperes}$. The mass of copper deposited at the cathode (atomic mass of $Cu = 63 \, u$) is ............ $g$.

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