A solution of a metal ion,when treated with K | vedclass

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(B) The reaction of $Hg^{2+}$ with $KI$ produces a red precipitate of $HgI_2$: $Hg^{2+} + 2KI \longrightarrow HgI_2 \downarrow 	ext{(red)} + 2K^+$In

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$Hg^{2+}$

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(B) The reaction of $Hg^{2+}$ with $KI$ produces a red precipitate of $HgI_2$: $Hg^{2+} + 2KI \longrightarrow HgI_2 \downarrow 	ext{(red)} + 2K^+$In excess $KI$,$HgI_2$ dissolves to form a colourless soluble complex,potassium tetraiodomercurate$(II)$: $HgI_2 + 2KI \longrightarrow K_2[HgI_4]$Additionally,$Hg^{2+}$ reacts with cobalt$(II)$ thiocyanate to form a deep blue crystalline precipitate of mercury$(II)$ tetrathiocyanatocobaltate$(II)$,$Hg[Co(SCN)_4]$: $Hg^{2+} + [Co(SCN)_4]^{2-} \longrightarrow Hg[Co(SCN)_4] \downarrow 	ext{(deep blue)}$Thus,the metal ion is $Hg^{2+}$.

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