$A$ solution of urea contains $8.6 \ g/L$ (mol. wt. $60.0$). It is isotonic with a $5\%$ solution of a non-volatile solute. The molecular weight of the solute will be:

At $300 \ K$,$6 \ g$ of urea was dissolved in $500 \ mL$ of water. What is the osmotic pressure (in $atm$) of the resultant solution? $(R=0.082 \ L \ atm \ K^{-1} \ mol^{-1})$ $(C=12; N=14; O=16; H=1)$

At constant temperature,the osmotic pressure of a solution is:

$A$ solution has an osmotic pressure of $x \ kPa$ at $300 \ K$ having $1 \ mole$ of solute in $10.5 \ m^{3}$ of solution. If its osmotic pressure is reduced to $(\frac{1}{10})$th of its initial value,what is the new volume of solution (in $m^{3}$)?

Equal masses of glucose,sucrose,and urea are dissolved in $V \ L$ of water to prepare separate solutions. The order of osmotic pressures $\pi_1, \pi_2$,and $\pi_3$ for glucose,sucrose,and urea respectively will be...........

Which solution is isotonic with $0.2 \ M \ H_2SO_4$?