A sonar device on a submarine sends out a sig | vedclass

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Question

(A) The total distance traveled by the sound signal is twice the distance between the submarine and the object,because the sound travels to the object

Vedclass · Accepted Answer

$1450$

Vedclass · Answer

(A) The total distance traveled by the sound signal is twice the distance between the submarine and the object,because the sound travels to the object and reflects back to the submarine.Total distance $(d)$ = $2 	imes 3625\, m = 7250\, m$.The time taken $(t)$ for the echo to return is $5\, s$.The speed of sound $(v)$ is calculated using the formula: $v = \frac{d}{t}$.Substituting the values: $v = \frac{7250\, m}{5\, s} = 1450\, m/s$.Therefore,the speed of sound in water is $1450\, m/s$.

$A$ sonar device on a submarine sends out a signal and receives an echo $5\, s$ later. Calculate the speed of sound in water if the distance of the object from the submarine is $3625\, m$. (in $, m/s$)

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