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Question

(A) The velocity of sound in a gaseous medium is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Since the temperature $T

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wavelength of the sound wave increases

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(A) The velocity of sound in a gaseous medium is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Since the temperature $T$ increases,the speed of sound $v$ also increases.The relationship between speed,frequency,and wavelength is $v = f \lambda$.Since the frequency $f$ is a characteristic of the source,it remains constant regardless of the medium's temperature.Therefore,$\lambda = \frac{v}{f}$. Since $v$ increases and $f$ is constant,the wavelength $\lambda$ must increase.Thus,the correct option is $(A)$.

$A$ source of frequency $f$ is emitting sound waves. If the temperature of the medium increases,then

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