A sphere of mass m is tied to one end of a st | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a horizontal circular motion,the centripetal force acts towards the center of the circle,while the displacement of the sphere at any instant is

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) In a horizontal circular motion,the centripetal force acts towards the center of the circle,while the displacement of the sphere at any instant is along the tangent to the circular path.Since the centripetal force is always perpendicular to the direction of displacement (velocity vector),the angle $	heta$ between the force and the displacement is $90^{\circ}$.The work done $W$ is given by the formula $W = F \cdot s \cdot \cos(	heta)$.Since $\cos(90^{\circ}) = 0$,the work done by the centripetal force in one full horizontal circle is $0$.

$A$ sphere of mass $m$ is tied to one end of a string of length $l$ and rotated through the other end along a horizontal circular path with speed $v$. The work done in a full horizontal circle is

Similar Questions

$A$ particle moves from position $3\hat i + 2\hat j - 6\hat k$ to $14\hat i + 13\hat j + 9\hat k$ due to a uniform force of $(4\hat i + \hat j + 3\hat k) \, N$. If the displacement is in meters,the work done will be ......... $J$.

$A$ force $\vec F = (5\hat i + 3\hat j) \ N$ is applied to a particle,which displaces it from its original position to the point $\vec s = (2\hat i - 1\hat j) \ m$. The work done on the particle is ......... $J$.

Work done

$A$ force of $(5\hat i + 6\hat j - 7\hat k) \, N$ is applied to a body of mass $10 \, kg$,causing it to displace from position $(4\hat i - 2\hat j + 5\hat k) \, m$ to $(8\hat i + 6\hat j - 3\hat k) \, m$. Calculate the work done in $J$.

The kinetic energy acquired by a body of mass $M$ in travelling a certain distance $d$,starting from rest,under the action of a constant force is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module