A spherical mirror is obtained as shown in th | vedclass

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(A) From the figure,the radius of curvature $R = 16 \ cm$. Since the inner surface is reflecting,it is a concave mirror.Focal length $f = \frac{R}{2}

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Inverted,real and magnified

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(A) From the figure,the radius of curvature $R = 16 \ cm$. Since the inner surface is reflecting,it is a concave mirror.Focal length $f = \frac{R}{2} = \frac{-16}{2} = -8 \ cm$.The object is placed at $u = -10 \ cm$.Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} + \frac{1}{-10} = \frac{1}{-8}$$\frac{1}{v} = \frac{1}{10} - \frac{1}{8} = \frac{4 - 5}{40} = \frac{-1}{40}$$v = -40 \ cm$.Magnification $m = \frac{-v}{u} = \frac{-(-40)}{-10} = -4$.Since $m$ is negative,the image is real and inverted. Since $|m| = 4 > 1$,the image is magnified.

$A$ spherical mirror is obtained as shown in the figure from a hollow glass sphere. If an object is positioned in front of the mirror,what will be the nature and magnification of the image of the object? (Figure drawn as schematic and not to scale)

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