A spherical source of power 4 W and frequency | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The intensity $I$ of a spherical wave at a distance $r$ from a source of power $P$ is given by the formula: $I = \frac{P}{A} = \frac{P}{4\pi r^2}$

Vedclass · Accepted Answer

$8 	imes 10^{-6} W/m^2$

Vedclass · Answer

(A) The intensity $I$ of a spherical wave at a distance $r$ from a source of power $P$ is given by the formula: $I = \frac{P}{A} = \frac{P}{4\pi r^2}$.Given: Power $P = 4 W$,distance $r = 200 m$.Substituting the values: $I = \frac{4}{4\pi 	imes (200)^2}$.$I = \frac{1}{\pi 	imes 40000} = \frac{1}{125663.7} W/m^2$.$I \approx 7.957 	imes 10^{-6} W/m^2$.Rounding to the nearest provided option,we get $I \approx 8 	imes 10^{-6} W/m^2$.

$A$ spherical source of power $4 W$ and frequency $800 Hz$ is emitting sound waves. The intensity of waves at a distance $200 m$ is

Similar Questions

$A$ point source is kept at the center of a spherically enclosed detector. If the volume of the detector is increased by $8$ times, the intensity will

The sound intensity level at a point $4 \,m$ from the point source is $10 \,dB$. Then the sound level at a distance $2 \,m$ from the same source will be ........ $dB$.

What is carried by the waves? Mass,velocity,or energy?

The intensity level at a distance of $200 \ cm$ from a sound source is $80 \ dB$. If there is no loss of acoustic power in the air and the threshold intensity of hearing is $10^{-12} \ W/m^2$,what is the intensity level at a distance of $400 \ cm$ from the source (in $dB$)?

If the ratio of intensities of two waves is $1 : 25$,then the ratio of their amplitudes will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module