$A$ steady current $i$ flows in a small square loop of wire of side $L$ in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let $\overrightarrow {{\mu _1}} $ and $\overrightarrow {{\mu _2}} $ respectively denote the magnetic moments due to the current loop before and after folding. Then

• A
  $\overrightarrow {{\mu _2}} = 0$
• B
  $\overrightarrow {{\mu _1}} $ and $\overrightarrow {{\mu _2}} $ are in the same direction
• C
  $\frac{{|\overrightarrow {{\mu _1}} |}}{{|\overrightarrow {{\mu _2}} |}} = \sqrt 2 $
• D
  $\frac{{|\overrightarrow {{\mu _1}} |}}{{|\overrightarrow {{\mu _2}} |}} = \frac{1}{{\sqrt 2 }}$