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(B) The formula for linear thermal expansion is given by $\Delta L = L_0 \alpha \Delta 	heta$.Here,$\Delta L$ is the allowed error in length,$L_0$ is

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$5$

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(B) The formula for linear thermal expansion is given by $\Delta L = L_0 \alpha \Delta 	heta$.Here,$\Delta L$ is the allowed error in length,$L_0$ is the original length,$\alpha$ is the coefficient of linear expansion,and $\Delta 	heta$ is the change in temperature.Given: $\Delta L = 5 	imes 10^{-5} \ mm$,$L_0 = 1 \ mm$ (as we are considering millimeter intervals),and $\alpha = 10 	imes 10^{-6} \ K^{-1}$.Rearranging the formula to solve for $\Delta 	heta$:$\Delta 	heta = \frac{\Delta L}{\alpha L_0} = \frac{5 	imes 10^{-5}}{10 	imes 10^{-6} 	imes 1} = \frac{5 	imes 10^{-5}}{10^{-5}} = 5 \ ^oC$.Thus,the maximum temperature variation allowable is $5 \ ^oC$.

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