$A$ steel wire has a length of $12.0 \;m$ and a mass of $2.10 \;kg$. What should be the tension in the wire so that the speed of a transverse wave on the wire equals the speed of sound in dry air at $20\,^{\circ}C = 343 \;m s^{-1}$?

$A$ uniform rope having some mass hangs vertically from a rigid support. $A$ transverse wave pulse is produced at the lower end. The speed $(v)$ of the wave pulse varies with height $(h)$ from the lower end as:

$A$ uniform string of length $20 \ m$ is suspended from a rigid support. $A$ short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is (take $g = 10 \ ms^{-2}$):

$A$ string of length $L$ is stretched by $\frac{L}{20}$ and the speed of transverse waves along it is $v$. The speed of the wave when it is stretched by $\frac{L}{10}$ will be (assume that Hooke's law is applicable).

$A$ copper wire is held at the two ends by rigid supports. At $50^{\circ} C$ the wire is just taut,with negligible tension. If $Y=1.2 \times 10^{11} \, N/m^2$,$\alpha=1.6 \times 10^{-5} /^{\circ} C$,and $\rho=9.2 \times 10^3 \, kg/m^3$,then the speed of transverse waves in this wire at $30^{\circ} C$ is .......... $m/s$.

One end of a string is tied to the ceiling of a lift and a load is attached at the bottom end of the string. When the lift is moving upwards with an acceleration of $2.1 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is $88 \,ms^{-1}$. If the lift moves downwards with an acceleration of $1.9 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is (take $g=10 \,ms^{-2}$): (in $\,ms^{-1}$)