A stone of 1, kg is thrown with a velocity of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Initial velocity of the stone,$u = 20\, m/s$.Final velocity of the stone,$v = 0\, m/s$.Distance covered by the stone,$s = 50\, m$.According to the

Vedclass · Accepted Answer

$-4$

Vedclass · Answer

(B) Initial velocity of the stone,$u = 20\, m/s$.Final velocity of the stone,$v = 0\, m/s$.Distance covered by the stone,$s = 50\, m$.According to the third equation of motion,$v^2 = u^2 + 2as$.Substituting the values: $(0)^2 = (20)^2 + 2 	imes a 	imes 50$.$0 = 400 + 100a$.$100a = -400$.$a = -4\, m/s^2$.The negative sign indicates that acceleration is acting against the motion of the stone.Mass of the stone,$m = 1\, kg$.From Newton's second law of motion,Force $F = m 	imes a$.$F = 1\, kg 	imes (-4\, m/s^2) = -4\, N$.Hence,the force of friction between the stone and the ice is $-4\, N$.

$A$ stone of $1\, kg$ is thrown with a velocity of $20\, m\ s^{-1}$ across the frozen surface of a lake and comes to rest after travelling a distance of $50\, m$. What is the force of friction (in $N$) between the stone and the ice?

Similar Questions

If action is always equal to the reaction,explain how a horse can pull a cart.

Why is it advised to tie any luggage kept on the roof of a bus with a rope?

An automobile vehicle has a mass of $1500 \, kg$. What must be the force (in $N$) between the vehicle and road if the vehicle is to be stopped with a negative acceleration of $1.7 \, m \, s^{-2}$?

An object of mass $100 \,kg$ is accelerated uniformly from a velocity of $5 \,m \,s^{-1}$ to $8 \,m \,s^{-1}$ in $6 \,s$. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

Explain,why is it difficult for a fireman to hold a hose,which ejects large amounts of water at a high velocity.

Vedclass Test Series

Exam Paper Generator

Online Exam Module