A stone tied to a string of length L is whirl | vedclass

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(D) Let the velocity at the lowest point be $v_1 = u$ (directed horizontally).When the string is horizontal,let the velocity be $v_2$. By the law of c

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$\sqrt{2(u^2 - gL)}$

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(D) Let the velocity at the lowest point be $v_1 = u$ (directed horizontally).When the string is horizontal,let the velocity be $v_2$. By the law of conservation of energy:$\frac{1}{2}mu^2 = \frac{1}{2}mv_2^2 + mgL$$v_2^2 = u^2 - 2gL$$v_2 = \sqrt{u^2 - 2gL}$ (directed vertically upwards).Since velocity is a vector,the change in velocity $\Delta \vec{v} = \vec{v}_2 - \vec{v}_1$.The magnitude is $|\Delta \vec{v}| = \sqrt{v_1^2 + v_2^2 - 2v_1v_2 \cos(90^\circ)}$.$|\Delta \vec{v}| = \sqrt{u^2 + (u^2 - 2gL)} = \sqrt{2u^2 - 2gL} = \sqrt{2(u^2 - gL)}$.

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