(D) Given:Moment of inertia $I = 0.20\, kg-m^2$Radius $r = 20\, cm = 0.2\, m$Force $F = 20\, N$Time $t = 5\, s$Initial angular velocity $\omega_0 = 0$

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(D) Given:Moment of inertia $I = 0.20\, kg-m^2$Radius $r = 20\, cm = 0.2\, m$Force $F = 20\, N$Time $t = 5\, s$Initial angular velocity $\omega_0 = 0$The torque applied to the wheel is $\tau = r \times F = 0.2\, m \times 20\, N = 4\, N-m$.Using the relation $\tau = I \alpha$,the angular acceleration is $\alpha = \frac{\tau}{I} = \frac{4}{0.20} = 20\, rad/s^2$.Using the equation of motion $\omega = \omega_0 + \alpha t$:$\omega = 0 + (20)(5) = 100\, rad/s$.

Class 11 Physics System of Particles and Rotational Motion Relation between Torque and Angular acceleration and it's Application

Medium

$A$ string is wrapped around the rim of a wheel of moment of inertia $0.20\, kg-m^2$ and radius $20\, cm$. The wheel is free to rotate about its axis and initially the wheel is at rest. The string is now pulled by a force of $20\, N$. The angular velocity of the wheel after $5\, s$ will be ....... $rad/s$.

A
$90$
B
$70$
C
$95$
D
$100$

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System of Particles and Rotational Motion

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Relation between Torque and Angular acceleration and it's Application

$A$ disc of mass $10 \ kg$ and radius $0.1 \ m$ is rotating at $120 \ rpm$. $A$ retarding torque brings it to rest in $10 \ s$. If the same torque is due to a force applied tangentially on the rim of the disc, then the magnitude of the force is: (in $\pi \ N$)

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$A$ horizontal heavy uniform bar of weight $W$ is supported at its ends by two men. At the instant one of the men lets go of his end of the rod,the force on the other man's hand changes to:

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What is the physical quantity of the time rate of the angular momentum?

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$A$ wheel with a moment of inertia of $5 \times 10^{-3} \ kg \cdot m^2$ is rotating at a rate of $20 \ rev/s$. The torque required to bring it to rest in $10 \ s$ is:

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Which of the following relations is incorrect?

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$A$ disc of mass $10 \ kg$ and radius $0.1 \ m$ is rotating at $120 \ rpm$. $A$ retarding torque brings it to rest in $10 \ s$. If the same torque is due to a force applied tangentially on the rim of the disc, then the magnitude of the force is: (in $\pi \ N$)

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What is the physical quantity of the time rate of the angular momentum?

$A$ wheel with a moment of inertia of $5 \times 10^{-3} \ kg \cdot m^2$ is rotating at a rate of $20 \ rev/s$. The torque required to bring it to rest in $10 \ s$ is:

Which of the following relations is incorrect?

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