$A$ string wave equation is given by $y=0.002 \sin (300 t-15 x)$ and the linear mass density is $\mu=0.1 \ kg/m$. Find the tension in the string (in $N$).

$A$ uniform metal wire has length $L$,mass $M$,and cross-sectional area $A$. It is under tension $T$,and $V$ is the speed of a transverse wave along the wire. The density of the wire is:

$A$ uniform rope having some mass hangs vertically from a rigid support. $A$ transverse wave pulse is produced at the lower end. The speed $(v)$ of the wave pulse varies with height $(h)$ from the lower end as:

$A$ uniform string is suspended vertically. $A$ transverse pulse is created at the top of the string. Then:

$A$ transverse wave propagating on a string can be described by the equation $y = 2 \sin (10x + 300t)$,where $x$ and $y$ are in meters and $t$ is in seconds. If the vibrating string has a linear mass density of $0.6 \times 10^{-3} \, g/cm$,then the tension in the string is .............. $N$.

$A$ heavy rope is suspended from a rigid support. $A$ transverse wave pulse is set up at the lower end,then