A structural steel rod has a radius of 10,mm | vedclass

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(A) Given: Force $F = 100\,kN = 10^5\,N$,Young's modulus $Y = 2 	imes 10^{11}\,N/m^2$,original length $L = 1.0\,m$,and radius $r = 10\,mm = 10^{-2}\,

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$0.16$

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(A) Given: Force $F = 100\,kN = 10^5\,N$,Young's modulus $Y = 2 	imes 10^{11}\,N/m^2$,original length $L = 1.0\,m$,and radius $r = 10\,mm = 10^{-2}\,m$.The area of cross-section $A = \pi r^2 = 3.14 	imes (10^{-2})^2 = 3.14 	imes 10^{-4}\,m^2$.From the definition of Young's modulus,$Y = \frac{	ext{Stress}}{	ext{Strain}} = \frac{F/A}{\Delta L/L}$.Therefore,$	ext{Strain} = \frac{F}{AY} = \frac{10^5}{3.14 	imes 10^{-4} 	imes 2 	imes 10^{11}}$.$	ext{Strain} = \frac{10^5}{6.28 	imes 10^7} = \frac{1}{628} \approx 0.00159$.Percentage strain = $	ext{Strain} 	imes 100 = 0.00159 	imes 100 \approx 0.16\%$.

$A$ structural steel rod has a radius of $10\,mm$ and length of $1.0\,m.$ $A$ $100\,kN$ force stretches it along its length. Young's modulus of structural steel is $2 \times 10^{11}\,N/m^2.$ The percentage strain is about ....... $\%$

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