A submarine emits a sonar pulse,which returns | vedclass

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Question

(A) To return the $SONAR$ pulse back,the sound wave has to travel the distance twice (to the cliff and back to the submarine).Given:Velocity $(v)$ of

Vedclass · Accepted Answer

$780.81$

Vedclass · Answer

(A) To return the $SONAR$ pulse back,the sound wave has to travel the distance twice (to the cliff and back to the submarine).Given:Velocity $(v)$ of sound wave $= 1531\, m/s$Total time $(t) = 1.02\, s$Total distance traveled by the sound wave $= v 	imes t$Total distance $= 1531\, m/s 	imes 1.02\, s = 1561.62\, m$Since the sound travels to the cliff and back,the distance to the cliff is half of the total distance traveled.Distance to the cliff $= 1561.62\, m / 2 = 780.81\, m$.

$A$ submarine emits a sonar pulse,which returns from an underwater cliff in $1.02\, s$. If the speed of sound in salt water is $1531\, m/s$,how far away is the cliff (in $, m$)?

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