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(B) The power $P$ supplied is used to maintain the substance in the molten state by compensating for the heat lost to the surroundings.When the power

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$\frac{Pt}{m}$

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(B) The power $P$ supplied is used to maintain the substance in the molten state by compensating for the heat lost to the surroundings.When the power is turned off,the substance solidifies by releasing its latent heat of fusion $L$ over time $t$.The total heat released during solidification is $Q = mL$.The rate of heat loss is $\frac{Q}{t} = \frac{mL}{t}$.Since the power $P$ was required to maintain the molten state,it must be equal to the rate of heat loss: $P = \frac{mL}{t}$.Solving for $L$,we get $L = \frac{Pt}{m}$.

Column-$I$	Column-$II$
$(a)$ Required heat to convert solid into gaseous.	$(i)$ Latent heat of fusion
$(b)$ Required heat to convert solid into liquid.	$(ii)$ Latent heat of vaporization

$A$ substance of mass $m \ kg$ requires a power input of $P \ W$ to remain in the molten state at its melting point. When the power is turned off,the sample completely solidifies in time $t \ s$. What is the latent heat of fusion of the substance?

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