A sulphide ore is first converted into its ox | vedclass

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(D) The reduction of metal sulphides is thermodynamically difficult because the enthalpy of formation of metal sulphides is less negative than that of

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$A$ metal oxide is generally more stable than the metal sulphide

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(D) The reduction of metal sulphides is thermodynamically difficult because the enthalpy of formation of metal sulphides is less negative than that of metal oxides. Conversely,the enthalpy of formation of $CO_2$ is more negative than that of $CS_2$,making carbon a suitable reducing agent for metal oxides but not for metal sulphides. Therefore,sulphide ores are first converted into metal oxides by roasting,which are then easily reduced to the metal.

$A$ sulphide ore is first converted into its oxide before reduction. This is done because

Similar Questions

When limestone is heated strongly,it gives off $CO_2$. In metallurgy,this process is known as:

Roasting is generally done in case of the following:

Which of the following statements,about the advantage of roasting of sulphide ore before reduction,is not true?

Select the correct statement:

$2CuFeS_2 + O_2 \rightarrow Cu_2S + 2FeS + SO_2$
Which process of metallurgy of copper is represented by the above equation?

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