$A$ surahi is the combination of

The volume of a cone with radius $5 \, cm$ and height $12 \, cm$ is ........ $\pi \, cm^{3}$.

The radius and height of a cone are both $3 \, cm$. Then,its volume is $\ldots \ldots \ldots \, cm^{3}$. (in $\pi$)

Curved surface area of a hemisphere $= \ldots \ldots \ldots . .$

The ratio of radii of two spheres is $3: 5$. Then,the ratio of their surface areas is $\ldots \ldots \ldots$.

The radii of the ends of a frustum of a cone of height $h \text{ cm}$ are $r_{1} \text{ cm}$ and $r_{2} \text{ cm}$. The volume in $\text{cm}^{3}$ of the frustum of the cone is: