$A$ system goes from $A$ to $B$ via two processes $I$ and $II$ as shown in the figure. If $\Delta U_I$ and $\Delta U_{II}$ are the changes in internal energies in the processes $I$ and $II$ respectively,then:

  • A
    $\Delta U_{II} > \Delta U_I$
  • B
    $\Delta U_{II} < \Delta U_I$
  • C
    $\Delta U_I = \Delta U_{II}$
  • D
    The relation between $\Delta U_I$ and $\Delta U_{II}$ cannot be determined.

Explore More

Similar Questions

$A$ gas in a closed container undergoes the cycle $ABCA$ as shown in the figure. The net heat released by the gas after it has undergone $20$ cycles is (in $\,kJ$)

The pressure of a gas changes linearly with volume from $A$ to $B$ as shown in the figure. If no heat is supplied to or extracted from the gas,then the change in the internal energy of the gas will be $............\,J$.

The pressure and volume of a gas are changed as shown in the $P-V$ diagram in this figure. The temperature of the gas will ........

$A$ thermodynamic system is taken through the cycle $PQRSP$ process as shown in the figure. The net work done by the system is .... $J$. (Note: $1 \text{ kp} = 10^3 \text{ Pa}$,$1 \text{ cc} = 10^{-6} \text{ m}^3$)

Difficult
View Solution

$A$ monoatomic ideal gas goes through a cyclic process as shown in the figure. The efficiency of this process is (in $\%$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo