A system of 100 kg mass undergoes a process | vedclass

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(B) The change in entropy of the system is given by $\Delta S_{system} = m 	imes (s_2 - s_1) = 100 \ kg 	imes (0.4 - 0.3) \ kJ \ kg^{-1} \ K^{-1} =

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$5$

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(B) The change in entropy of the system is given by $\Delta S_{system} = m 	imes (s_2 - s_1) = 100 \ kg 	imes (0.4 - 0.3) \ kJ \ kg^{-1} \ K^{-1} = 10 \ kJ \ K^{-1}$.The change in entropy of the surrounding is given by $\Delta S_{surrounding} = S_{2,surr} - S_{1,surr} = 75 \ kJ \ K^{-1} - 80 \ kJ \ K^{-1} = -5 \ kJ \ K^{-1}$.The entropy change of the universe is $\Delta S_{universe} = \Delta S_{system} + \Delta S_{surrounding} = 10 \ kJ \ K^{-1} + (-5 \ kJ \ K^{-1}) = 5 \ kJ \ K^{-1}$.

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