A tangent is drawn to the ellipse frac{x^2}{3 | vedclass

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(C) The equation of the ellipse is $\frac{x^2}{32} + \frac{y^2}{8} = 1$. Comparing with $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,we have $a^2 = 32$ and

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$3$

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(C) The equation of the ellipse is $\frac{x^2}{32} + \frac{y^2}{8} = 1$. Comparing with $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,we have $a^2 = 32$ and $b^2 = 8$. The center $C$ is at $(0, 0)$. The point $A$ is $(8, 0)$,which lies on the major axis. For an ellipse,the property of the normal at point $P$ meeting the major axis at $B$ and the tangent from $A$ is given by $CB \cdot CA = a^2 - b^2$. Here,$CA = 8$,$a^2 = 32$,and $b^2 = 8$. Substituting the values: $CB \cdot 8 = 32 - 8$. $CB \cdot 8 = 24$. $CB = \frac{24}{8} = 3 	ext{ units}$.

$A$ tangent is drawn to the ellipse $\frac{x^2}{32} + \frac{y^2}{8} = 1$ from the point $A(8, 0)$ to touch the ellipse at point $P$. If the normal at $P$ meets the major axis of the ellipse at point $B$,then the length $BC$ is equal to (where $C$ is the center of the ellipse) - ............ $units$

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