(B) According to Bernoulli's principle,the pressure at the bottom of the tank is equal to the sum of the hydrostatic pressures of the two liquids.$P =

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(B) According to Bernoulli's principle,the pressure at the bottom of the tank is equal to the sum of the hydrostatic pressures of the two liquids.$P = h_w \rho_w g + h_k \rho_k g$Here,$h_w = 3\,m$,$\rho_w = 1000\,kg/m^3$,$h_k = 2\,m$,and $\rho_k = 0.8 \times 1000 = 800\,kg/m^3$.$P = (3 \times 1000 \times 10) + (2 \times 800 \times 10) = 30000 + 16000 = 46000\,Pa$.Using Torricelli's law for the exit velocity $v$ at the bottom,where the pressure energy is converted into kinetic energy:$P = \frac{1}{2} \rho_w v^2$$46000 = \frac{1}{2} \times 1000 \times v^2$$v^2 = \frac{46000 \times 2}{1000} = 92$$v = \sqrt{92} \approx 9.6\,ms^{-1}$.

Class 11 Physics Fluid Mechanics and Surface Tension Velocity of Efflux and Torricelli's law

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$A$ tank with a small hole at the bottom has been filled with water and kerosene (specific gravity $0.8$). The height of water is $3\,m$ and that of kerosene $2\,m$. When the hole is opened,the velocity of fluid coming out from it is nearly ........ $ms^{-1}$. (Take $g = 10\,ms^{-2}$ and density of water $= 10^3\,kg\,m^{-3}$)

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Class 11

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Fluid Mechanics and Surface Tension

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Velocity of Efflux and Torricelli's law

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$A$ large tank filled with water to a height $h$ is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from $h$ to $h/2$ and from $h/2$ to $0$ is

MediumAP EAMCET 2003

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$A$ vessel is filled with water up to a height $h$. When a hole is made at the bottom,all the water drains out in time $t$. If the vessel is filled with water up to a height $4h$,how long will it take for the water to drain out completely when a hole is made at the bottom?

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