A telephonic communication service is working | vedclass

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Question

(B) The total bandwidth available for transmission is $10\%$ of the carrier frequency.Total available bandwidth $= 10\% 	ext{ of } 10 \ GHz = 0.10

Vedclass · Accepted Answer

$2 	imes 10^5$

Vedclass · Answer

(B) The total bandwidth available for transmission is $10\%$ of the carrier frequency.Total available bandwidth $= 10\% 	ext{ of } 10 \ GHz = 0.10 	imes 10 	imes 10^9 \ Hz = 10^9 \ Hz$.Let $n$ be the number of telephonic channels that can be transmitted simultaneously.Each channel requires a bandwidth of $5 \ kHz = 5 	imes 10^3 \ Hz$.The total bandwidth used by $n$ channels is $n 	imes 5 	imes 10^3 \ Hz$.Equating the total available bandwidth to the bandwidth required by $n$ channels:$n 	imes 5 	imes 10^3 = 10^9$$n = \frac{10^9}{5 	imes 10^3} = \frac{10^6}{5} = 0.2 	imes 10^6 = 2 	imes 10^5$.Therefore,$2 	imes 10^5$ telephonic channels can be transmitted simultaneously.

$A$ telephonic communication service is working at a carrier frequency of $10 \ GHz$. Only $10\%$ of it is utilized for transmission. How many telephonic channels can be transmitted simultaneously if each channel requires a bandwidth of $5 \ kHz$?

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