A tent is cylindrical at the base and conical | vedclass

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Question

(C) The total surface area of the tent is the sum of the curved surface area of the cylinder and the curved surface area of the cone.Radius $(r)$ = $1

Vedclass · Accepted Answer

$44$

Vedclass · Answer

(C) The total surface area of the tent is the sum of the curved surface area of the cylinder and the curved surface area of the cone.Radius $(r)$ = $1.2\, m$.Height of cylinder $(h_1)$ = $4\, m$.Height of cone $(h_2)$ = $3.5\, m$.Slant height of the cone $(l)$ = $\sqrt{r^2 + h_2^2} = \sqrt{(1.2)^2 + (3.5)^2} = \sqrt{1.44 + 12.25} = \sqrt{13.69} = 3.7\, m$.Curved surface area of cylinder = $2\pi rh_1 = 2 	imes \frac{22}{7} 	imes 1.2 	imes 4 \approx 30.17\, m^2$.Curved surface area of cone = $\pi rl = \frac{22}{7} 	imes 1.2 	imes 3.7 \approx 13.95\, m^2$.Total area = $30.17 + 13.95 = 44.12\, m^2$.Rounding to the nearest whole number,the cloth used is $44\, m^2$.

Part $I$	Part $II$
$1.$ $CSA$ of a cylinder	$a.$ $3\pi r^2$
$2.$ $CSA$ of a sphere	$b.$ $2\pi rh$
$3.$ $CSA$ of a cone	$c.$ $4\pi r^2$
$4.$ $TSA$ of a hemisphere	$d.$ $\pi rl$

$A$ tent is cylindrical at the base and conical at the top. Its radius is $1.2\, m$. The height of the cylindrical part is $4\, m$ and the height of the conical part is $3.5\, m$. How many square metres of cloth is used to make the tent?

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$2.$ $CSA$ of a sphere $b.$ $2\pi rh$

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