A thin flat circular disc of radius 4.5 ,cm i | vedclass

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(D) The excess force required to pull a circular disc of radius $R$ from the surface of a liquid with surface tension $T$ is given by the force due to

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$19.8 \,mN$

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(D) The excess force required to pull a circular disc of radius $R$ from the surface of a liquid with surface tension $T$ is given by the force due to surface tension acting along the circumference of the disc.Excess force $F = T 	imes (2 \pi R)$Given:Radius $R = 4.5 \,cm = 4.5 	imes 10^{-2} \,m$Surface tension $T = 0.07 \,N \,m^{-1}$Substituting the values:$F = 0.07 	imes 2 	imes 3.14 	imes 4.5 	imes 10^{-2}$$F = 0.07 	imes 28.26 	imes 10^{-2}$$F = 1.9782 	imes 10^{-2} \,N$$F \approx 19.8 	imes 10^{-3} \,N$$F = 19.8 \,mN$

$A$ thin flat circular disc of radius $4.5 \,cm$ is placed gently over the surface of water. If the surface tension of water is $0.07 \,N \,m^{-1}$, then the excess force required to take it away from the surface is

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