$A$ train $100 \, m$ long is moving with a velocity of $60 \, km/h$. Find the time it takes to cross a bridge $1 \, km$ long.
(66 S) Length of the train $= 100 \, m = 0.1 \, km$.
Length of the bridge $= 1 \, km$.
Total distance to be covered to cross the bridge $= \text{Length of train} + \text{Length of bridge} = 0.1 \, km + 1 \, km = 1.1 \, km$.
Velocity of the train $= 60 \, km/h$.
Time taken $(t) = \frac{\text{Total distance}}{\text{Velocity}} = \frac{1.1 \, km}{60 \, km/h} = \frac{1.1}{60} \, h$.
To convert time into seconds, multiply by $3600 \, s/h$:
$t = \frac{1.1}{60} \times 3600 \, s = 1.1 \times 60 \, s = 66 \, s$.
Length of the bridge $= 1 \, km$.
Total distance to be covered to cross the bridge $= \text{Length of train} + \text{Length of bridge} = 0.1 \, km + 1 \, km = 1.1 \, km$.
Velocity of the train $= 60 \, km/h$.
Time taken $(t) = \frac{\text{Total distance}}{\text{Velocity}} = \frac{1.1 \, km}{60 \, km/h} = \frac{1.1}{60} \, h$.
To convert time into seconds, multiply by $3600 \, s/h$:
$t = \frac{1.1}{60} \times 3600 \, s = 1.1 \times 60 \, s = 66 \, s$.
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