A train starts from station A at 9, am and tr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The first train starts at $9\, am$ and travels for $2$ hours until the second train starts at $11\, am$.$2$. Distance covered by the first tr

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(A) $1$. The first train starts at $9\, am$ and travels for $2$ hours until the second train starts at $11\, am$.$2$. Distance covered by the first train in $2$ hours $= 50\, km/h 	imes 2\, h = 100\, km$.$3$. Remaining distance between the two trains at $11\, am = 210\, km - 100\, km = 110\, km$.$4$. Since the trains are moving towards each other,their relative speed $= 50\, km/h + 60\, km/h = 110\, km/h$.$5$. Time taken to meet after $11\, am = \frac{	ext{Remaining Distance}}{	ext{Relative Speed}} = \frac{110\, km}{110\, km/h} = 1\, hour$.$6$. The trains meet at $12\, pm$ (noon).$7$. Total distance from station $A$ at the meeting point = (Distance covered by first train in $2$ hours) + (Distance covered by first train in $1$ hour after $11\, am$) = $100\, km + (50\, km/h 	imes 1\, h) = 150\, km$.

$A$ train starts from station $A$ at $9\, am$ and travels at $50\, km/h$ towards station $B,$ which is $210\, km$ away. Another train starts from station $B$ at $11\, am$ and travels at $60\, km/h$ towards station $A.$ At what distance from station $A$ will they meet? (in $km$)

Similar Questions

Ravi and Ajay start simultaneously from a place $A$ towards $B$,$60 \, km$ apart. Ravi's speed is $4 \, km/h$ less than that of Ajay. Ajay,after reaching $B$,turns back and meets Ravi at a place $12 \, km$ away from $B$. Ravi's speed is (in $km/h$):

$A$ $320\, m$ long train moving at an average speed of $120\, km/h$ crosses a platform in $24\, seconds$. $A$ man crosses the same platform in $4\, minutes$. What is the speed of the man in $m/s$?

$A$ train covers a distance of $10 \text{ km}$ in $12 \text{ minutes}$. If its speed is decreased by $5 \text{ km/hr}$,the time taken by it to cover the same distance will be:

If a train runs at $40 \text{ km/h}$,it reaches its destination late by $11 \text{ minutes}$. But if it runs at $50 \text{ km/h}$,it is late by $5 \text{ minutes}$ only. The correct time (in $\text{minutes}$) for the train to complete the journey is

$A$ man walks a certain distance and rides back in $4 \, h \, 30 \, min$. He could ride both ways in $3 \, h$. The time required by the man to walk both ways is?

Vedclass Test Series

Exam Paper Generator

Online Exam Module