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(D) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_1$ and a receiving antenna of height $h_2$ is given by the form

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$57.28$

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(D) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_1$ and a receiving antenna of height $h_2$ is given by the formula:$d = \sqrt{2Rh_1} + \sqrt{2Rh_2}$Given:$h_1 = 50\, m = 50 	imes 10^{-3}\, km$$h_2 = 80\, m = 80 	imes 10^{-3}\, km$$R = 6400\, km$Substituting the values:$d = \sqrt{2 	imes 6400 	imes 50 	imes 10^{-3}} + \sqrt{2 	imes 6400 	imes 80 	imes 10^{-3}}$$d = \sqrt{640000 	imes 10^{-3}} + \sqrt{1024000 	imes 10^{-3}}$$d = \sqrt{640} + \sqrt{1024}$$d = 25.30 + 32 = 57.30\, km$Rounding to the nearest provided option,the range is $57.28\, km$.

Column $A$	Column $B$
$A$. $D$-layer	$I$. $250-400 \ km$
$B$. $E$-layer	$II$. $170-190 \ km$
$C$. $F_1$-layer	$III$. $95-120 \ km$
$D$. $F_2$-layer	$IV$. $65-75 \ km$

$A$ transmitting antenna at the top of a tower has a height of $50\, m$ and the height of the receiving antenna is $80\, m$. What is the range of communication for Line of Sight (LoS) mode? (In $km$)
[Use radius of earth $R = 6400\, km$]

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$A$ transmitting antenna at the top of a tower has a height of $50\, m$ and the height of the receiving antenna is $80\, m$. What is the range of communication for Line of Sight (LoS) mode? (In $km$)[Use radius of earth $R = 6400\, km$]