A triangular park ABC has sides 120,m, 80,m a | vedclass

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(B) To find the area of the park,we use Heron's formula.First,calculate the semi-perimeter $s$:$2s = 50\,m + 80\,m + 120\,m = 250\,m$$s = 125\,m$Now,c

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$Rs. 4940$

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(B) To find the area of the park,we use Heron's formula.First,calculate the semi-perimeter $s$:$2s = 50\,m + 80\,m + 120\,m = 250\,m$$s = 125\,m$Now,calculate the differences:$s - a = 125\,m - 120\,m = 5\,m$$s - b = 125\,m - 80\,m = 45\,m$$s - c = 125\,m - 50\,m = 75\,m$Area of the park $= \sqrt{s(s-a)(s-b)(s-c)}$$= \sqrt{125 	imes 5 	imes 45 	imes 75}\,m^2$$= \sqrt{2109375}\,m^2 = 375\sqrt{15}\,m^2$Next,calculate the cost of fencing:Perimeter of the park $= 250\,m$Length of wire needed $= 250\,m - 3\,m = 247\,m$Cost of fencing $= 247\,m 	imes Rs. 20/m = Rs. 4940$

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