A truck starts from rest and rolls down a hil | vedclass

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(A) Given:Initial velocity, $u = 0 \, m/s$Distance traveled, $S = 400 \, m$Time taken, $t = 20 \, s$Mass of the truck, $m = 7 \, 	ext{metric tons} =

Vedclass · Accepted Answer

Acceleration = $2 \, m/s^2$, Force = $14000 \, N$

Vedclass · Answer

(A) Given:Initial velocity, $u = 0 \, m/s$Distance traveled, $S = 400 \, m$Time taken, $t = 20 \, s$Mass of the truck, $m = 7 \, 	ext{metric tons} = 7000 \, kg$$(a)$ To find the acceleration $(a)$:Using the second equation of motion, $S = ut + \frac{1}{2}at^2$$400 = (0)(20) + \frac{1}{2} 	imes a 	imes (20)^2$$400 = \frac{1}{2} 	imes a 	imes 400$$a = \frac{400 	imes 2}{400} = 2 \, m/s^2$$(b)$ To find the force $(F)$:Using Newton's second law of motion, $F = m 	imes a$$F = 7000 \, kg 	imes 2 \, m/s^2 = 14000 \, N$

$A$ truck starts from rest and rolls down a hill with constant acceleration. It travels a distance of $400 \, m$ in $20 \, s$. Find its acceleration. Find the force acting on it, if its mass is $7$ metric tons.

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