A truck of mass M is moved under a force F. I | vedclass

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(C) According to Newton's second law of motion,the acceleration $a$ is given by $a = \frac{F}{m}$.Initially,the acceleration of the truck is $a_1 = \f

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(C) According to Newton's second law of motion,the acceleration $a$ is given by $a = \frac{F}{m}$.Initially,the acceleration of the truck is $a_1 = \frac{F}{M}$.When the truck is loaded with an object of mass equal to the truck,the new mass becomes $M' = M + M = 2M$.The driving force is halved,so the new force becomes $F' = \frac{F}{2}$.The new acceleration $a_2$ is given by $a_2 = \frac{F'}{M'} = \frac{F/2}{2M} = \frac{F}{4M}$.Comparing the new acceleration with the initial acceleration: $\frac{a_2}{a_1} = \frac{F/4M}{F/M} = \frac{1}{4}$.Therefore,the acceleration becomes one-fourth of its original value.

$A$ truck of mass $M$ is moved under a force $F$. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved,then how does the acceleration change?

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