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(D) The chemical formula of calcium fluoride is $CaF_2$. In the $CaF_2$ crystal structure (fluorite structure),$Ca^{2+}$ ions form a face-centered cub

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$8$

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(D) The chemical formula of calcium fluoride is $CaF_2$. In the $CaF_2$ crystal structure (fluorite structure),$Ca^{2+}$ ions form a face-centered cubic $(fcc)$ lattice. The number of $Ca^{2+}$ ions per unit cell is $4$ (since $8$ corners $	imes 1/8 + 6$ faces $	imes 1/2 = 4$). Since the stoichiometry is $1:2$,for every $Ca^{2+}$ ion,there are $2$ $F^{-}$ ions. Therefore,the number of $F^{-}$ ions per unit cell is $4 	imes 2 = 8$.

$A$ unit cell of calcium fluoride has four calcium ions. The number of fluoride ions in the unit cell is

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