A wall has two layers A and B, each made of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In steady state, the rate of heat flow $(H)$ through both layers $A$ and $B$ is the same.$H = \frac{K_A A \Delta T_A}{L} = \frac{K_B A \Delta T_B}

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) In steady state, the rate of heat flow $(H)$ through both layers $A$ and $B$ is the same.$H = \frac{K_A A \Delta T_A}{L} = \frac{K_B A \Delta T_B}{L}$Since the area $(A)$ and thickness $(L)$ are the same for both layers, we have:$K_A \Delta T_A = K_B \Delta T_B$Given that the thermal conductivity of $A$ is twice that of $B$, $K_A = 2K_B$:$2K_B \Delta T_A = K_B \Delta T_B$$\Delta T_B = 2 \Delta T_A$The total temperature difference across the wall is $\Delta T_A + \Delta T_B = 36^{\circ}C$.Substituting $\Delta T_B = 2 \Delta T_A$ into the equation:$\Delta T_A + 2 \Delta T_A = 36^{\circ}C$$3 \Delta T_A = 36^{\circ}C$$\Delta T_A = 12^{\circ}C$.

Similar Questions

The magnifying power of a simple microscope is (when the final image is formed at $D = 25 \ cm$ from the eye):

The minimum value of $2x^2+x-1$ is:

The displacement of a particle executing $SHM$ is given by $y=5 \sin \left(4 t+\frac{\pi}{3}\right)$. If $T$ is the time period and the mass of the particle is $2 \text{ g}$,the kinetic energy of the particle when $t=\frac{T}{4}$ is given by (in $J$)

Identify the organism shown in the given figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module