A wave is represented by x = 4 cos left(8t - | vedclass

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(A) The given wave equation is $x = 4 \cos \left(8t - \frac{y}{2}\right)$.Comparing this with the standard wave equation form $x = A \cos (\omega t -

Vedclass · Accepted Answer

$\frac{4}{\pi}$

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(A) The given wave equation is $x = 4 \cos \left(8t - \frac{y}{2}ight)$.Comparing this with the standard wave equation form $x = A \cos (\omega t - ky)$,we get the angular frequency $\omega = 8 	ext{ rad/s}$.We know that the relationship between angular frequency $\omega$ and frequency $f$ is given by $\omega = 2\pi f$.Substituting the value of $\omega$:$8 = 2\pi f$$f = \frac{8}{2\pi} = \frac{4}{\pi} 	ext{ s}^{-1}$.Thus,the frequency of the wave is $\frac{4}{\pi} 	ext{ s}^{-1}$.

$A$ wave is represented by $x = 4 \cos \left(8t - \frac{y}{2}\right)$,where $x$ and $y$ are in $m$ and $t$ is in $s$. The frequency of the wave (in $s^{-1}$) is .........

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