x- अक्ष के अनुदिश गतिमान एक तरंग का समीकरण y( | vedclass

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(A) तरंग का सामान्य समीकरण $y(x, t) = A \cos(kx - \omega t)$ होता है।यहाँ,$k = \alpha$ और $\omega = \beta$ है।तरंग संख्या $k$ का सूत्र $k = \frac{2\pi

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$\alpha = 25.00\pi, \beta = \pi$

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(A) तरंग का सामान्य समीकरण $y(x, t) = A \cos(kx - \omega t)$ होता है।यहाँ,$k = \alpha$ और $\omega = \beta$ है।तरंग संख्या $k$ का सूत्र $k = \frac{2\pi}{\lambda}$ है।दिया गया है $\lambda = 0.08 \ m$,इसलिए $\alpha = \frac{2\pi}{0.08} = 25\pi \ rad/m$।कोणीय आवृत्ति $\omega$ का सूत्र $\omega = \frac{2\pi}{T}$ है।दिया गया है $T = 2.0 \ s$,इसलिए $\beta = \frac{2\pi}{2.0} = \pi \ rad/s$।अतः,सही विकल्प $A$ है।

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