A wheel is rotating at 900 r.p.m. about its | vedclass

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(A) The initial angular velocity is $\omega_{0} = 900 \ r.p.m. = \frac{900 	imes 2\pi}{60} \ rad/s = 30\pi \ rad/s$. Since the wheel comes to rest,th

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$\pi/2$

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(A) The initial angular velocity is $\omega_{0} = 900 \ r.p.m. = \frac{900 	imes 2\pi}{60} \ rad/s = 30\pi \ rad/s$. Since the wheel comes to rest,the final angular velocity is $\omega = 0 \ rad/s$. The time taken is $t = 1 \ minute = 60 \ s$. Using the equation of rotational motion $\omega = \omega_{0} + \alpha t$,where $\alpha$ is the angular acceleration: $0 = 30\pi + \alpha(60)$. $\alpha = -\frac{30\pi}{60} = -\frac{\pi}{2} \ rad/s^2$. The angular retardation is the magnitude of angular acceleration,which is $\frac{\pi}{2} \ rad/s^2$.

$A$ wheel is rotating at $900 \ r.p.m.$ about its axis. When the power is cut-off,it comes to rest in $1 \ minute$. The angular retardation in $rad/s^2$ is

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