A wind with speed 40,m/s blows parallel to th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Bernoulli's principle,the pressure above the roof decreases as the wind speed increases.The pressure difference $\Delta P$ between th

Vedclass · Accepted Answer

$2.4 	imes 10^5\,N,$ upwards

Vedclass · Answer

(B) According to Bernoulli's principle,the pressure above the roof decreases as the wind speed increases.The pressure difference $\Delta P$ between the inside and outside of the roof is given by $\Delta P = \frac{1}{2} ho V^2$.Given: $ho = 1.2\,kg/m^3$,$V = 40\,m/s$,and $A = 250\,m^2$.$\Delta P = \frac{1}{2} 	imes 1.2 	imes (40)^2 = 0.6 	imes 1600 = 960\,Pa$.The force exerted on the roof is $F = \Delta P 	imes A$.$F = 960 	imes 250 = 240,000\,N = 2.4 	imes 10^5\,N$.Since the pressure outside is lower than the pressure inside,the net force acts in the upward direction.

$A$ wind with speed $40\,m/s$ blows parallel to the roof of a house. The area of the roof is $250\,m^2.$ Assuming that the pressure inside the house is atmospheric pressure,the force exerted by the wind on the roof and the direction of the force will be $(\rho_{air} = 1.2\,kg/m^3)$

Similar Questions

The angle of a prism is $A.$ One of its refracting surfaces is silvered. Light rays falling at an angle of incidence $2A$ on the first surface return back through the same path after suffering reflection at the silvered surface. The refractive index $\mu$ of the prism is

If ${a^x} = {b^y} = {(ab)^{xy}},$ then $x + y = $

$\int_0^1 \sin \left(2 \tan ^{-1} \sqrt{\frac{1+x}{1-x}}\right) d x$ is equal to :

Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound:

Which of the following statements is incorrect?

Vedclass Test Series

Exam Paper Generator

Online Exam Module