A wire is 1.0 , m long,0.2 , mm in diameter a | vedclass

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(A) Given: Length $L = 1.0 \, m$,Diameter $D = 0.2 \, mm = 0.2 	imes 10^{-3} \, m$.Radius $r = D/2 = 0.1 	imes 10^{-3} \, m = 10^{-4} \, m$.Resistan

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$3.14 	imes 10^{-7} \, \Omega \cdot m$

Vedclass · Answer

(A) Given: Length $L = 1.0 \, m$,Diameter $D = 0.2 \, mm = 0.2 	imes 10^{-3} \, m$.Radius $r = D/2 = 0.1 	imes 10^{-3} \, m = 10^{-4} \, m$.Resistance $R = 10 \, \Omega$.Formula for resistivity: $ho = \frac{R \cdot A}{L}$,where $A = \pi r^2$.Substituting the values: $A = 3.14 	imes (10^{-4})^2 = 3.14 	imes 10^{-8} \, m^2$.$ho = \frac{10 	imes 3.14 	imes 10^{-8}}{1.0} = 3.14 	imes 10^{-7} \, \Omega \cdot m$.

$A$ wire is $1.0 \, m$ long,$0.2 \, mm$ in diameter and has a resistance of $10 \, \Omega$. Calculate the resistivity of its material.

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