A wire of length 314 , cm carrying a current | vedclass

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(B) The length of the wire $L = 314 \, cm = 3.14 \, m$.When the wire is bent into a circle of radius $R$,the circumference is $2 \pi R = L$.$2 	imes

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$11$

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(B) The length of the wire $L = 314 \, cm = 3.14 \, m$.When the wire is bent into a circle of radius $R$,the circumference is $2 \pi R = L$.$2 	imes 3.14 	imes R = 3.14 \implies R = 0.5 \, m$.The area of the coil is $A = \pi R^2 = 3.14 	imes (0.5)^2 = 3.14 	imes 0.25 = 0.785 \, m^2$.The magnetic moment $M$ is given by $M = I 	imes A$.$M = 14 \, A 	imes 0.785 \, m^2 = 10.99 \, A \cdot m^2$.Rounding to the nearest integer,we get $M \approx 11 \, A \cdot m^2$.

$A$ wire of length $314 \, cm$ carrying a current of $14 \, A$ is bent to form a circle. The magnetic moment of the coil is $........ \, A \cdot m^2$. [Given $\pi = 3.14$]

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