A Zener diode of power rating 1.6,W is to be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power rating of the Zener diode is $P = 1.6\,W$ and the breakdown voltage is $V_z = 8\,V$.The maximum current that can flow through the Zener

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The power rating of the Zener diode is $P = 1.6\,W$ and the breakdown voltage is $V_z = 8\,V$.The maximum current that can flow through the Zener diode is $I_{z,max} = \frac{P}{V_z} = \frac{1.6\,W}{8\,V} = 0.2\,A$.For the Zener diode to act as a voltage regulator, the input voltage $V_{in}$ must be greater than the breakdown voltage $V_z$. Here, the input voltage fluctuates between $3\,V$ and $10\,V$. The Zener diode will only regulate when $V_{in} \geq 8\,V$. Therefore, we consider the maximum input voltage $V_{in,max} = 10\,V$ to ensure the diode does not exceed its power rating.The voltage drop across the series resistance $R_s$ at maximum input voltage is $V_{R_s} = V_{in,max} - V_z = 10\,V - 8\,V = 2\,V$.To ensure safe operation, the current through the series resistance $R_s$ must be equal to the maximum current the Zener diode can handle (assuming no load current is connected, which is the worst-case scenario for the diode).Thus, $R_s = \frac{V_{R_s}}{I_{z,max}} = \frac{2\,V}{0.2\,A} = 10\,\Omega$.

Similar Questions

What is the current flowing through the Zener diode in the given circuit in $mA$?

Mention the use of a Zener diode.

$A$ Zener diode is connected to a battery and a load resistance as shown below. The currents $I, I_Z$ and $I_L$ respectively are:

Consider the following statements $(A)$ and $(B)$ and identify the correct answer.
$(A)$ $A$ Zener diode is connected in reverse bias when used as a voltage regulator.
$(B)$ The potential barrier of a $p-n$ junction typically lies between $0.1 \, V$ to $0.3 \, V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module