A ball of mass m is thrown vertically upwards | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the mass of the ball be $m$. The forces acting on the ball are the gravitational force ($mg$ acting downwards) and the air resistance force ($

Vedclass · Accepted Answer

$g$

Vedclass · Answer

(C) Let the mass of the ball be $m$. The forces acting on the ball are the gravitational force ($mg$ acting downwards) and the air resistance force ($F_r = -kv$,where $k$ is a constant and $v$ is the velocity).At any point,the net force is $F_{net} = -mg - kv$ (taking upward as positive).The acceleration is $a = F_{net}/m = -g - (k/m)v$.At the highest point,the velocity $v$ of the ball is $0$.Substituting $v = 0$ into the acceleration equation: $a = -g - (k/m)(0) = -g$.The magnitude of the acceleration is $|a| = g$.

$A$ ball of mass $m$ is thrown vertically upwards. Assume the force of air resistance has magnitude proportional to the velocity,and direction opposite to the velocity. At the highest point,the ball's acceleration is

Similar Questions

$A$ body is thrown vertically upwards with a velocity of $19.6 \, ms^{-1}$. The position of the body after $4 \, s$ will be

What is the ratio of the distances covered by a freely falling body in the $1^{st}$,$2^{nd}$,and $3^{rd}$ seconds of its motion?

Suggest a suitable physical situation for the following $v-t$ graph.

$A$ $0.4\,kg$ mass takes $8\,s$ to reach the ground when dropped from a certain height $P$ above the surface of the Earth. The loss of potential energy in the last second of the fall is $..............J$. [Take $g = 10\,m/s^2$]

$A$ body is projected vertically upward with a velocity of $20 \, m/s$ from the top of a tower of height $200 \, m$. With what velocity will it strike the ground (in $m/s$)? (Take $g = 10 \, m/s^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module