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(D) From the acceleration-time graph,we can observe three distinct phases of motion:$1$. In the first phase,the acceleration $a$ is constant and posit

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(D) From the acceleration-time graph,we can observe three distinct phases of motion:$1$. In the first phase,the acceleration $a$ is constant and positive. Since $v = \int a \, dt$,the velocity increases linearly with time,represented by a straight line with a positive slope on a velocity-time graph.$2$. In the second phase,the acceleration $a = 0$. This means the velocity remains constant,represented by a horizontal line on a velocity-time graph.$3$. In the third phase,the acceleration $a$ is again constant and positive. This means the velocity increases linearly with time again,represented by a straight line with a positive slope.Comparing this with the given options,the graph that shows a linear increase in velocity,followed by a constant velocity,and then another linear increase is option $D$.

The acceleration-time graph of a body is shown. The corresponding velocity-time graph of the same body is

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