According to $VSEPR$ theory,the most probable shape of the molecule having $4$ electron pairs in the outer shell of the central atom is

  • A
    Linear
  • B
    Tetrahedral
  • C
    Hexahedral
  • D
    Octahedral

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The shape of $XeF^{+}_3$ is

In a regular octahedral molecule $MX_6$,the number of $X-M-X$ bond angles of $180^{\circ}$ is:

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The shape of the $XeF_4$ molecule is:

Which of the following is isoelectronic as well as has same structure as that of $N_2O$?

Which one is correct for bond angle?

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