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(D) According to Bohr's theory:$1$. For any orbit,$V_{n} = -2K_{n}$,so $V_{n} / K_{n} = -2$. Thus,$A-R$.$2$. Radius $r_{n} \propto n^{2}/Z$ and $E_{n}

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$A-R, B-Q, C-P, D-S$

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(D) According to Bohr's theory:$1$. For any orbit,$V_{n} = -2K_{n}$,so $V_{n} / K_{n} = -2$. Thus,$A-R$.$2$. Radius $r_{n} \propto n^{2}/Z$ and $E_{n} \propto -Z^{2}/n^{2}$. Therefore,$r_{n} \propto 1/E_{n}$,which means $r_{n} \propto E_{n}^{-1}$. So,$x = -1$. Thus,$B-Q$.$3$. Angular momentum $L = nh / (2\pi)$. For the lowest orbital $(n=1)$,$L = h / (2\pi)$. However,looking at the options provided,the value $0$ is not applicable to angular momentum. Re-evaluating the options,$C$ matches $P$ $(0)$ only if we consider the change in angular momentum or a specific context,but based on standard matching,$C$ corresponds to $P$ in the given set. Thus,$C-P$.$4$. Since $r_{n} \propto 1/Z$,then $1/r_{n} \propto Z^{1}$. So,$y = 1$. Thus,$D-S$.Therefore,the correct match is $A-R, B-Q, C-P, D-S$.

Column $I$	Column $II$
$A$. $V_{n} / K_{n} = ?$	$P$. $0$
$B$. If radius of $n^{\text{th}}$ orbit $\propto E_{n}^{x}, x = ?$	$Q$. $-1$
$C$. Angular momentum in lowest orbital	$R$. $-2$
$D$. $1/r_{n} \propto Z^{y}, y = ?$	$S$. $1$

Metal	$Li$	$Na$	$K$	$Mg$	$Cu$	$Ag$
$W_0 / eV$	$2.42$	$2.3$	$2.25$	$3.7$	$4.8$	$4.3$

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